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(D) The conversion of $Borax$ $(Na_2B_4O_7 \cdot 10H_2O)$ to $H_3BO_3$ is achieved by treatment with $HCl$:$Na_2B_4O_7 + 2HCl + 5H_2O \rightarrow 2NaC

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$HCl, Al$

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(D) The conversion of $Borax$ $(Na_2B_4O_7 \cdot 10H_2O)$ to $H_3BO_3$ is achieved by treatment with $HCl$:$Na_2B_4O_7 + 2HCl + 5H_2O \rightarrow 2NaCl + 4H_3BO_3$$H_3BO_3$ on heating gives $B_2O_3$:$2H_3BO_3 \xrightarrow{\Delta} B_2O_3 + 3H_2O$Finally,$B_2O_3$ is reduced to crystalline boron using $Al$:$B_2O_3 + 2Al \xrightarrow{\Delta} 2B + Al_2O_3$Note: Reduction with $Mg$ yields amorphous boron. Thus,$X = HCl$ and $Y = Al$.

Borax is converted into crystalline boron by the following steps:
$Borax$ $\xrightarrow{X} H_3BO_3$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow[\Delta]{Y} B$
$X$ and $Y$ are respectively:

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Borax is converted into crystalline boron by the following steps:$Borax$ $\xrightarrow{X} H_3BO_3$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow[\Delta]{Y} B$$X$ and $Y$ are respectively: